1.8=50t-16t^2

Solution for 1.8=50t-16t^2 equation:

1.8=50t-16t^2

We move all terms to the left:

1.8-(50t-16t^2)=0

We get rid of parentheses

16t^2-50t+1.8=0

a = 16; b = -50; c = +1.8;
Δ = b2-4ac
Δ = -502-4·16·1.8
Δ = 2384.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-\sqrt{2384.8}}{2*16}=\frac{50-\sqrt{2384.8}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+\sqrt{2384.8}}{2*16}=\frac{50+\sqrt{2384.8}}{32}
$